I'm sure this is an easy one, but can anyone explain how this is done?

I believe it's an integration by parts problem, but I'm having trouble deciding what to call u and dv. Thanks. I'm new, so sorry if I broke any understood etiquette! =)

Printable View

- October 27th 2008, 11:08 PMdisasterologyintegration by parts?
I'm sure this is an easy one, but can anyone explain how this is done?

I believe it's an integration by parts problem, but I'm having trouble deciding what to call u and dv. Thanks. I'm new, so sorry if I broke any understood etiquette! =) - October 27th 2008, 11:33 PMRedBarchetta
Try pulling out the constant first. Then applying integration by parts, but don't forget to multiply by the constant when you're finished.

Remember this acronym:

LIPET:**L**og Function,**I**nverse Trig Function,**P**ower Function,**E**xponential Function,**T**rig Function

This helps in how you in choosing u, with the highest priority given in order starting with logs, inverse trig, etc. This should make the selection of u and v easier, as is the goal of the parts method is to make the integral of v du easier than your original integral.