Is there any easy way to find the convergence/divergence of this series?
So far I tried using the integral test and came up with a convergence at 20.
This involves integration by substitution. Is there any easier method?
Follow Math Help Forum on Facebook and Google+
Hello, Originally Posted by RedBarchetta Is there any easier method? Maybe : hence .
As one has, for sufficiently large, hence that is to say . As is an absolutely convergent series, the series converges too. (comparison test)
View Tag Cloud