Originally Posted by
U-God I would attempt it like this:
let $\displaystyle f(p) = p + \frac{1}{p} $
$\displaystyle f'(p) = 1 - \frac{1}{p^2} $
for stationary point let $\displaystyle f'(p) = 0 $
this implies that $\displaystyle \frac{1}{p^2} = 1 $
so $\displaystyle p = +/- 1 $