Originally Posted by
Mathstud28 Im assuming you are asking to find $\displaystyle \frac{d}{dx}\bigg[\arcsin\left(\frac{3}{x^2}\right)\bigg]$?
You have two options...you could use the fact that $\displaystyle \arcsin\left(\frac{1}{x}\right)=\csc^{-1}\left(x\right)$ to eliminate the problem negative exponent...this is assuming you know that derivative...or just use the chain rule
$\displaystyle \frac{d}{dx}\bigg[\arcsin\left(\frac{3}{x^2}\right)\bigg]=\frac{1}{\sqrt{1-\left(\frac{3}{x^2}\right)^2}}\cdot\left[\frac{3}{x^2}\right]'$
EDIT: The war begins anew...