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Thread: how to show sinx uni converges

  1. October 26th 2008, 05:12 AM #1
    szpengchao
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    how to show sinx uni converges

    y_{n}(x)=\sin(x), 0\leq |x| \leq 2\pi n and

    y_{n}(x)=0, 2\pi n< |x| <\infty
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  2. October 27th 2008, 02:42 AM #2
    CaptainBlack
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    Quote Originally Posted by szpengchao View Post
    y_{n}(x)=\sin(x), 0\leq |x| \leq 2\pi n and

    y_{n}(x)=0, 2\pi n< |x| <\infty
    y_n(x) converges pointwise to \sin(x) ,but for all n there exists x_n such that |y_n(x_n)-\sin(x_n)|=1.

    CB
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