Originally Posted by
Chocolatelover2 Hello everyone,
Could you please tell me if this is correct?
FInd the directional derivative using f(x, y, z)=xy+z^2 as you leave the point (1,1,0) heading in the direction of the point (0,1,1)
u=-i+0j+1k
fx=y (0,1.1)--> 1
fy=x --> 1
fz=2z-->0
u=v/magnitude= -i+1k/square root (-1^2+1^2)= -1i+k/square root (2)
directional derivative=i+j(-1/square root of 2i+1/square root of 2k)
(i+j)(-1/square root 2i+1/square root of 2k)
gradient (1,0,0)=i+j+0k
direction derivative= gradient(u)
Thank you very much