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Math Help - limit as t goes to negative infinity...

  1. #1
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    limit as t goes to negative infinity...

    what is the limit of:

    lim (t --> negative infinity) 1/e^t
    ?

    because in this form the denominator shoots to negative infinity while the top remains 1, so it seems 0

    but you can rewrite it as lim (t --> negative infinity) e^(-t)
    where (-t) --> infinity as t --> negative infinity

    and in this form we have an exponent shooting to infinity, so it seems like the answer is infinity

    I ran into this problem late last night, so maybe I was just tired and didn't see something obvious, but I'm a bit confused about this, can anyone help?
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  2. #2
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    Quote Originally Posted by minivan15 View Post
    because in this form the denominator shoots to negative infinity
    e^t>0 and lim t-> -infinity e^t=0.
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  3. #3
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    Quote Originally Posted by treetheta View Post
    \lim_{t\to-\infty} \frac{1}{e^t} = 0<br />
    Think about that again!
    \lim_{t\to-\infty} \frac{1}{e^t} =\lim_{t\to-\infty} {e^{-t}}= ?

    If t=-100 then what is {e^{-t}}= ?
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