what is the limit of:
lim (t --> negative infinity) 1/e^t
?
because in this form the denominator shoots to negative infinity while the top remains 1, so it seems 0
but you can rewrite it as lim (t --> negative infinity) e^(-t)
where (-t) --> infinity as t --> negative infinity
and in this form we have an exponent shooting to infinity, so it seems like the answer is infinity
I ran into this problem late last night, so maybe I was just tired and didn't see something obvious, but I'm a bit confused about this, can anyone help?