what is the limit of:

lim (t --> negative infinity) 1/e^t

?

because in this form the denominator shoots to negative infinity while the top remains 1, so it seems 0

but you can rewrite it as lim (t --> negative infinity) e^(-t)

where (-t) --> infinity as t --> negative infinity

and in this form we have an exponent shooting to infinity, so it seems like the answer is infinity

I ran into this problem late last night, so maybe I was just tired and didn't see something obvious, but I'm a bit confused about this, can anyone help?