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Math Help - Can someone please help me

  1. #1
    Junior Member
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    Can someone please help me

    i'm having trouble with this step function question, i know it has to be done using laplace transforms but getting stuck any help would be appreciated

    y"+2y = r(t) y(0)=y'(0)=0

    r(t)= 1 0<t<1
    0 otherwise

    and this question i found the homogeneous solutions (e^x and e^2x) but am having trouble finding the particular solution, i'm been trying to use varation of parameters

    x^2y"-2xy'+2y=1/x^2
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  2. #2
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by action259 View Post
    i'm having trouble with this step function question, i know it has to be done using laplace transforms but getting stuck any help would be appreciated

    y"+2y = r(t) y(0)=y'(0)=0

    r(t)= 1 0<t<1
    0 otherwise

    and this question i found the homogeneous solutions (e^x and e^2x) but am having trouble finding the particular solution, i'm been trying to use varation of parameters

    x^2y"-2xy'+2y=1/x^2
    Hint: Write r(t) in terms of the Heaviside step function. Specifically
    r(t) = u(t) - u(t-1)
    Where
    u(t) = 0; t<0
    u(t) = 1; t>0

    -Dan
    Last edited by topsquark; September 16th 2006 at 06:14 AM. Reason: Wrong symbol
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