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- September 16th 2006, 06:32 AM #1

- Joined
- Aug 2006
- Posts
- 34

## Can someone please help me

i'm having trouble with this step function question, i know it has to be done using laplace transforms but getting stuck any help would be appreciated

y"+2y = r(t) y(0)=y'(0)=0

r(t)= 1 0<t<1

0 otherwise

and this question i found the homogeneous solutions (e^x and e^2x) but am having trouble finding the particular solution, i'm been trying to use varation of parameters

x^2y"-2xy'+2y=1/x^2

- September 16th 2006, 07:12 AM #2