integrate question:
$\displaystyle
= \int (3sin(4x+5) - 6cos(7-8x)) dx
$
any help, im thinking it has to do with identities?
It looks kind of evil, but it's actually not that difficult. You can split it up into two different integrals. $\displaystyle 3\int (sin(4x+5))dx - 6\int (cos(7-8x))dx$
Now use u-subs, taking the 4x+5 and the 7-8x to be the u's for the two different integrals. I think it yields:
$\displaystyle (-3/4)cos(4x+5) +(3/4)sin(7-8x) + C$