$\displaystyle f(x) = cos(sin(cos x)) $ so far ive gotten to here (below) but now im stuck $\displaystyle f'(x) = -sin(sin(cos x)) \cdot cos(cos x) \cdot (-sin x) $ last one <3 haha
Follow Math Help Forum on Facebook and Google+
$\displaystyle f'(x) = \sin[\sin(\cos{x})] \cdot \cos(\cos{x}) \cdot \sin{x} $ double negative factors yield a positive ... that's about it.
View Tag Cloud