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Thread: last derivative

  1. October 23rd 2008, 04:27 PM #1
    iz1hp
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    last derivative

    <br /> <br /> f(x) = cos(sin(cos x))<br />

    so far ive gotten to here (below) but now im stuck

    <br /> <br /> f'(x) = -sin(sin(cos x)) \cdot cos(cos x) \cdot (-sin x)<br />

    last one <3 haha
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  2. October 23rd 2008, 04:42 PM #2
    skeeter
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    f'(x) = \sin[\sin(\cos{x})] \cdot \cos(\cos{x}) \cdot \sin{x}<br />

    double negative factors yield a positive ... that's about it.
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