Thread: hellpp!! please!!

ok i need help on find aymptotes
2.) find the slant asymptote of the curve. This, use it to help graph the curve.

so i have a equation like this
Y= x^2 + 9 / x
y= x^2 - 2x - 1/x
y= x^3/x2-1

can u help and teach me what to do , cause my teacher told us to use long division to find the slant asympototes.

Originally Posted by lickman

ok i need help on find aymptotes
2.) find the slant asymptote of the curve. This, use it to help graph the curve.

so i have a equation like this
Y= x^2 + 9 / x
y= x^2 - 2x - 1/x
y= x^3/x2-1

can u help and teach me what to do , cause my teacher told us to use long division to find the slant asympototes.

Divide the numerator by the denominator and exclude the remainder.

You have a slant asymptote at
You also have a vertical asymptote at since the denominator cannot be 0.
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Divide the numerator by the denominator and exclude the remainder.

You have a slant asymptote at
You also have a vertical asymptote at since the denominator cannot be 0.
-------------------------------------------------------------------


Divide the numerator by the denominator and exclude the remainder.

You have a slant asymptote at
You also have 2 vertical asymptotes at since the denominator cannot be 0.

Originally Posted by lickman

can u help and teach me what to do , cause my teacher told us to use long division to find the slant asympototes.

To help you with slant asymptotes and polynomial long division, you might look here: Slant, or Oblique, Asymptotes

i kinda get what u say by dividing but can u clearify how u got the slant aysmtopes? cause u told me to divide, and then u get the slant aysmotopes as the quotient. but how do u divide such number of these x^2 -2x - 1 / x