ok i need help on find aymptotes
2.) find the slant asymptote of the curve. This, use it to help graph the curve.

so i have a equation like this
Y= x^2 + 9 / x
y= x^2 - 2x - 1/x
y= x^3/x2-1

can u help and teach me what to do , cause my teacher told us to use long division to find the slant asympototes.

2. Originally Posted by lickman
ok i need help on find aymptotes
2.) find the slant asymptote of the curve. This, use it to help graph the curve.

so i have a equation like this
Y= x^2 + 9 / x
y= x^2 - 2x - 1/x
y= x^3/x2-1

can u help and teach me what to do , cause my teacher told us to use long division to find the slant asympototes.
$\displaystyle y=\frac{x^2+9}{x}$

Divide the numerator by the denominator and exclude the remainder.

You have a slant asymptote at $\displaystyle y=x$
You also have a vertical asymptote at $\displaystyle x=0$ since the denominator cannot be 0.
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$\displaystyle y=\frac{x^2-2x-1}{x}$

Divide the numerator by the denominator and exclude the remainder.

You have a slant asymptote at $\displaystyle y=x-2$
You also have a vertical asymptote at $\displaystyle x=0$ since the denominator cannot be 0.
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$\displaystyle y=\frac{x^3}{x^2-1}$

Divide the numerator by the denominator and exclude the remainder.

You have a slant asymptote at $\displaystyle y=x$
You also have 2 vertical asymptotes at $\displaystyle x=1 \ \ and \ \ x=-1$ since the denominator cannot be 0.

3. Originally Posted by lickman
can u help and teach me what to do , cause my teacher told us to use long division to find the slant asympototes.
To help you with slant asymptotes and polynomial long division, you might look here: Slant, or Oblique, Asymptotes

4. i kinda get what u say by dividing but can u clearify how u got the slant aysmtopes? cause u told me to divide, and then u get the slant aysmotopes as the quotient. but how do u divide such number of these x^2 -2x - 1 / x