I was just wandering if we had say , if we had to find the limit of that as it approached -2 for example.
Could I cancel both top and bottom by (x + 2)^2, or would that not be correct since (x+2) = 0 when x = -2
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ummm im not surei know u could write it as but im not sure if ur allowed to cancel since the bottom tends to 0.
Hello, Originally Posted by Lipticboven ummm im not surei know u could write it as but im not sure if ur allowed to cancel since the bottom tends to 0. You can simplify, and that's the principle of these limits.
So, firstly without working with limits,
You can simplify, because you don't know yet top and bottom are 0. There's no problem.
Now, take the limit as x tends to 2.
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