1. ## Antiverivative check!

Get the anti-derivative of

$

= 5x^3 - 6x + 7\sqrt[3]{x} - 8 + \frac{9}{\sqrt{x}} - \frac{10}{x} + \frac{11}{x^3}

$

is

$

= \frac{5}{4}x^4 - 3x^2 + \frac{21}{4}x^\frac{4}{3} - 8x + 18x^\frac{1}{2} - 0 - \frac{11}{2}x^{-2} + C

$

correct??? thank u

2. Originally Posted by jvignacio
Get the anti-derivative of

$

= 5x^3 - 6x + 7\sqrt[3]{x} - 8 + \frac{9}{\sqrt{x}} - \frac{10}{x} + \frac{11}{x^3}

$

is

$

= \frac{5}{4}x^4 - 3x^2 + \frac{21}{4}x^\frac{4}{3} - 8x + 18x^\frac{1}{2} - 0 - \frac{11}{2}x^{-2} + C

$

correct??? thank u
That 0 should be ln actually.

Otherwise it looks fine to me unless I missed something.

$

= \frac{5}{4}x^4 - 3x^2 + \frac{21}{4}x^\frac{4}{3} - 8x + 18x^\frac{1}{2} - 10 \ln (x) - \frac{11}{2}x^{-2} + C

$

3. Originally Posted by janvdl
That 0 should be ln actually.

Otherwise it looks fine to me unless I missed something.

$

= \frac{5}{4}x^4 - 3x^2 + \frac{21}{4}x^\frac{4}{3} - 8x + 18x^\frac{1}{2} - 10 \ln (x) - \frac{11}{2}x^{-2} + C

$
thanks mateeee!! dont know why it shud be 10ln(x) tho?