1. ## help

so i have a problem f(x) = -16/(x-7)^2 + 4
so i was asked to find the root.
I know the VA(vertical aymsotopes) is 7, and the denominator is alrdy put into a vertex form V(7,4)
my teacher taught us to pull out the 16, so u get y= -16[1/(x-7)^2 + 4
so when u find the root do, u include the -16 in it too? or do u just work with the bracket and apply the -16 last. can u please tell which way is correct, or show me your way i guess.

Thanks

2. $f(x) = \frac{-16}{(x-7)^2} + 4$
$0 = \frac{-16}{(x-7)^2} + 4$
$-4 = \frac{-16}{(x-7)^2}$
$-4 \cdot (x-7)^2 = -16$
$(x-7)^2 = 4$
$x-7 = \pm 2$
$x = \pm 2 +7$