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Thread: help

  1. #1
    Junior Member
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    help

    so i have a problem f(x) = -16/(x-7)^2 + 4
    so i was asked to find the root.
    I know the VA(vertical aymsotopes) is 7, and the denominator is alrdy put into a vertex form V(7,4)
    my teacher taught us to pull out the 16, so u get y= -16[1/(x-7)^2 + 4
    so when u find the root do, u include the -16 in it too? or do u just work with the bracket and apply the -16 last. can u please tell which way is correct, or show me your way i guess.


    Thanks
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  2. #2
    Senior Member vincisonfire's Avatar
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    $\displaystyle f(x) = \frac{-16}{(x-7)^2} + 4 $
    $\displaystyle 0 = \frac{-16}{(x-7)^2} + 4 $
    $\displaystyle -4 = \frac{-16}{(x-7)^2} $
    $\displaystyle -4 \cdot (x-7)^2 = -16 $
    $\displaystyle (x-7)^2 = 4 $
    $\displaystyle x-7 = \pm 2 $
    $\displaystyle x = \pm 2 +7 $
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