# Math Help - Solving Integrals

1. ## Solving Integrals

Hey Everyone

I'm having a little trouble solving this integral.

Its kinda hard to do it without the symbols but i'll try my best.

~ dx / (x^2 -9) ^ (3/2)

Now I know the (3/2) power would make the denominator:

dx / square root ( (x^2 - 9 ) ^ 3)

I'm just not entirely sure where to head from there. Any suggestions?

2. you could try the substitution
x =3 cosh(u) if you know about hyperbolic functions

3. $\int{\frac{dx}{\left( x^{2}-9 \right)^{3/2}}}=\int{\frac{dx}{\left( x^{2}-9 \right)\sqrt{x^{2}-9}}},$ and put $x=\frac1u.$