I have a term test coming Nov 5th, so my posts will be here for the next couple weeks while I cram to complete my homework. Here goes:

If f(x)=(x^2)+10sinx, show that there is a number c such that f(c)=1000

This is what I have so far:

make the function equal 1000, so,

1000=(c^2)+10sin(c)

I would like to solve for c now, but for some reason, the idea in the SSM says that the IVT applies here. I would like to just start plugging in trial numbers to see what values I can get slightly above and below 1000, but I'm not even too sure on how to evaluate (let's say) 10sin(20) without a calculator.

How do I go about continuing to solve this not knowing how to evaluate the sin of my trial numbers without a calculator?