I don't seem to understand how to completely differentiate this equation on both sides (implicit differentiation):
x^3-xy+y^2=4
Am I doing this right:
3x^2-(x'y+xy')+2yy'=0
Any help would be appreciated
Thanks
I don't seem to understand how to completely differentiate this equation on both sides (implicit differentiation):
x^3-xy+y^2=4
Am I doing this right:
3x^2-(x'y+xy')+2yy'=0
Any help would be appreciated
Thanks
Okay so you know that the product rule is: assuming both f and g are functions of x.
however, if f(x) = x, then f'(x) = 1
Therefore
In your case, g = y.
When I said you can differentiate the x parts directly, I was referring to how inside the parenthesis you left the derivative of x as x'. You could have omitted this and left it as 1.