y=1/(1+x^2), y=0, x=0, x=2 about x=2 Setup the integral for the volume. So, I know it's a version of 2pi integral of the height and c, but I don't know what those are.
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$\displaystyle V = 2\pi \int_0^2 (2-x) \cdot \frac{1}{1+x^2} \, dx$
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