# Thread: Find the area enclosed by the parametric curve

1. ## Find the area enclosed by the parametric curve

Find the area enclosed by the x-axis and the curve x = 1+e^t, y = t-t^2

My work:

ln(x-1) = t

y = ln (x-1) - (ln (x-1))^2

Area = Integral from 2 to e+1 of (t-t^2)(e^t) dt

After integrating I get e^t(1+t-t^2) from 0 to e+1

Which turns out to be something like -10. What am I doing wrong?

2. Originally Posted by veronicak5678
Find the area enclosed by the x-axis and the curve x = 1+e^t, y = t-t^2

My work:

ln(x-1) = t

y = ln (x-1) - (ln (x-1))^2

Area = Integral from 2 to e+1 of (t-t^2)(e^t) dt x goes from 2 to e+1.

After integrating I get e^t(1+t-t^2) from 0 to e+1 But t goes from 0 to 1.

Which turns out to be something like -10. What am I doing wrong?
..

3. Got it. Thanks for answering!

,

,

,

### ym tttt. .com v.com.computerttg .com.com ".com.comttycfttccgf.b vbh.bb.vvht.g v. tt . g t ! . tfftfc v ctttgg tvvtv.tv yh t . .y tt.com.com.com.com.com.com.com.comygc.co.inff.computerry.com txty.comtvyb ybyb.6vvv6 bvyynub tv

Click on a term to search for related topics.