Please explain to me how you do it, thanksQuote:
Find the lines that are a) tangent and b) normal to the curve at the given point.
y= 2 sin (pi x-y) (1,0)
Printable View
Please explain to me how you do it, thanksQuote:
Find the lines that are a) tangent and b) normal to the curve at the given point.
y= 2 sin (pi x-y) (1,0)
anyone? (Crying)
1. find $\displaystyle \frac{dy}{dx}$
2. determine the slope of the tangent line by substituting x = 1 and y = 0 into the derivative expression, $\displaystyle \frac{dy}{dx}$.
3. use the point-slope form of a linear equation to find the tangent line equation.
remember this? ... $\displaystyle y - y_1 = m(x - x_1)$
4. the normal line passes through the same point and is perpendicular to the tangent line ... use the perpendicular slope and repeat step #3.
