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Math Help - help with Reciprocal of qudratic function

  1. #1
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    help with Reciprocal of qudratic function

    i've been given a question like this :
    h(x) = 1 / - (4x^2 - 4x -3 )
    So far , i've been asked to first find the roots, the roots/Aysmptopes, where y = 1, where y = -1 , and the y-int.
    how do u get the vertex, and how do u know when something is opening up or downwards.
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  2. #2
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    Quote Originally Posted by lickman View Post
    i've been given a question like this :
    h(x) = 1 / - (4x^2 - 4x -3 )
    So far , i've been asked to first find the roots, the roots/Aysmptopes, where y = 1, where y = -1 , and the y-int.
    how do u get the vertex, and how do u know when something is opening up or downwards.
    Draw the graph of y = h(x) by considering the graph of y = g(x) = -(4x^2 - 4x - 3) .......

    y = h(x) has vertical asymptotes where y = g(x) has x-intercepts.

    y = h(x) has a minimum turning point at the value of x where y = g(x) has its maximum turning point

    etc.
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