how would i find the taylor series for xe^x at b=1
i know the known taylor series for e^x but what do I do if there's an x in front and b=1
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Just write it as
EDIT: I used the Maclaurin series, but you get the idea.
how would this look in the sigma form? I check the answer and it had some 'e' there. how about b=1
If , and :
Since , we get
Or in Sigma form:
Last edited by Spec; October 20th 2008 at 01:08 PM.
Reason: b=1 and not 2 :(
where did u get 2+t?
Originally Posted by khuezy where did u get 2+t? Sorry, I read your original post as for some reason.
this isn't in the taylor series formation right?
Originally Posted by khuezy
this isn't in the taylor series formation right? It's the same as since
if b=2 then
Originally Posted by khuezy if b=2 then
that's the answer key to the problem. How come they look so different?
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