Use the shell method to find the volume of the solid generated by revolving the region bounded by the given curves and lines about the x-axis.

X=2sqrt(y), x= - 2y, y=1

A) (16/3) pi B) (22/15) pi C) 4pi D) (44/15)pi

2. Thus,
y=-(1/2) x
y=(1/4)x^2

Thus,
I hope you are asking for this,
EDIT: It should be (1/4)x^2 not (1/2)x^2