Can someone tell me if this is right? 6x^2-3y^2=9 the answer I can up with is y'=12x divided by 6y Just a yes or no would really be apprecaited
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Originally Posted by tkasskim Can someone tell me if this is right? 6x^2-3y^2=9 the answer I can up with is y'=12x divided by 6y Just a yes or no would really be apprecaited $\displaystyle 6x^2-3y^2=9$ $\displaystyle 12xdx -6ydy =0$ $\displaystyle -6ydy=-12xdx$ $\displaystyle dy = \frac{-12x}{-6y}dx$ $\displaystyle \frac{dy}{dx} = \frac{2x}{y}$ You forgot to simplify lol
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