# Math Help - implicit differentation

1. ## implicit differentation

Can someone tell me if this is right?

6x^2-3y^2=9

the answer I can up with is y'=12x divided by 6y

Just a yes or no would really be apprecaited

2. Originally Posted by tkasskim
Can someone tell me if this is right?

6x^2-3y^2=9

the answer I can up with is y'=12x divided by 6y

Just a yes or no would really be apprecaited
$6x^2-3y^2=9$

$12xdx -6ydy =0$

$-6ydy=-12xdx$

$dy = \frac{-12x}{-6y}dx$

$\frac{dy}{dx} = \frac{2x}{y}$

You forgot to simplify lol