# implicit differentation

• October 19th 2008, 06:35 PM
tkasskim
implicit differentation
Can someone tell me if this is right?

6x^2-3y^2=9

the answer I can up with is y'=12x divided by 6y

Just a yes or no would really be apprecaited
• October 19th 2008, 07:51 PM
11rdc11
Quote:

Originally Posted by tkasskim
Can someone tell me if this is right?

6x^2-3y^2=9

the answer I can up with is y'=12x divided by 6y

Just a yes or no would really be apprecaited

$6x^2-3y^2=9$

$12xdx -6ydy =0$

$-6ydy=-12xdx$

$dy = \frac{-12x}{-6y}dx$

$\frac{dy}{dx} = \frac{2x}{y}$

You forgot to simplify lol