Thread: Tangent lines and derivatives Help!

1. Tangent lines and derivatives Help!

I can solve derivatives alright but I don't understand tangent lines at all.
Find the equation of the tangent line to the curve at the point . The equation of this tangent line can be written in the form
where m is?
And b is?
I solved the derivative down to
6[2sin(x)+sec(x)tan(x)]
I think this is right and hopefully you needed to solve the derivative.
Thanks to anyone who can help
Casas4

2. If $\displaystyle f$ is differentiable at $\displaystyle x_0$ then the equation of the tangent line at $\displaystyle \left( {x_0 ,f\left( {x_0 } \right)} \right)$ is $\displaystyle y = f'\left( {x_0 } \right)\left( {x - x_0 } \right) + f\left( {x_0 } \right)$.
Note that $\displaystyle f'\left( {x_0 } \right)$ is the slope of the tangent line.

3. still confused

do i plug in (pi/3,6) with the equation y-y1=m(x-X1)? If so how do you turn the derivative in to an equation?

4. Originally Posted by Casas4
do i plug in (pi/3,6) with the equation y-y1=m(x-X1)? If so how do you turn the derivative in to an equation?
By asking that question, you have told me that you need some real help that is beyond an “On-Line” environment.
You need a sit-down with a live instructor.