Thread: Tangent lines and derivatives Help!

I can solve derivatives alright but I don't understand tangent lines at all.
Find the equation of the tangent line to the curve at the point . The equation of this tangent line can be written in the form
where m is?
And b is?
I solved the derivative down to
6[2sin(x)+sec(x)tan(x)]
I think this is right and hopefully you needed to solve the derivative.
Thanks to anyone who can help
Casas4

If is differentiable at then the equation of the tangent line at is .
Note that is the slope of the tangent line.

do i plug in (pi/3,6) with the equation y-y1=m(x-X1)? If so how do you turn the derivative in to an equation?

Originally Posted by Casas4

do i plug in (pi/3,6) with the equation y-y1=m(x-X1)? If so how do you turn the derivative in to an equation?

By asking that question, you have told me that you need some real help that is beyond an “On-Line” environment.
You need a sit-down with a live instructor.
Please ask your instructor to help you.