don't waste your time trying to simplify this mess, just sub in t = 0 ... you get a(0) = 0
solve the quadratic factor for r.
Hi, can someone help me with these?
A particle moves along the x-axis, its position at time t is given by x(t) = 9t / 3+8t^2, t>0 where t is seconds and x is meters
The acceleration of the particle equals 0 at time t=_____ and t=_____ seconds
So I found the second derivative to be this big mess:
(-1296t^2 - 6912t^4 - 9216t^6 - 2592t + 18432t^5) / (9 +48t^2 +64t^4)^2
^ I hope this is right, but maybe it's where I went wrong
then I know to set the equation equal to 0, but then I don't know what to do next, any help?
also I need help with this question:
The function y = e^rx satisfies the equation y'' - 7.4y' + 12y = 0 if r=____ or if r=____
no idea what to do here.
thanks in advance!