use implicit differentiation to find the slope of the tangent line to the curve
y/(x-3y) = x^6 + 8 at the point (1, 9/28)
m = ?
i tried using quotient rule but cannot seem to get the correct answer. this is what i have done
[(dy/dx)(x-3y)-(1-3dy/dx)(y)]/(x-3y)^2 = 6x^5
--> [x(dy/dx)]/(x-3y)^2 = 6x^5 + y
dy/dx = [(6x^5 + y)(x-3y)^2]/x