If $\displaystyle g(t)= sin(f(-t, t, 2t))$ find $\displaystyle g'(t)$. im not sure exactly how to approach this one.
I still dont really get it.. heres my stab it
$\displaystyle f(c(t)) = sin(f(-t,t,2t))$
$\displaystyle g'(t)= cos(f(-t, t, 2t) \cdot c('t)$
Is this right.... or am i completely wrong.. i really need to see a computation of this the above examples really haven't helped me