More likely a Physicist thing. Actually it would be:

**F(x,y)** = (Integral from (2,pi) to (x,y)) (-2u(v^2)sin(u^2v)

**i**du + (cos((u^2)v) - u^2(v)(sin((u^2)v)

**j**dv)

(or something) according to the problem statement. But, as ThePerfectHacker says, we need a path to integrate on. Unless this just happens to be path independent? Then again, we don't know which of "u" or "v" is the "x" or "y" component either, so even if the integral IS path independent, we still can't do the integral... (jcarlos, jump in here at any time!

)

-Dan