find dy/dx by implicit differentiation x^2-2xy+y^3=c
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Originally Posted by thecount find dy/dx by implicit differentiation x^2-2xy+y^3=c implicit differentiation is just the chain rule, where the derivative of y is dy/dx. just take the derivative of that equation if x is a function of y, and c is a constant: 2x - 2x*dy/dx - 2y + 3y^2*dy/dx = 0 dy/dx (-2x + 3y^2)= 2y-2x dy/dx = (2y-2x)/(-2x + 3y^2)
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