Thanks for the quick reply, Moo.
Sorry, I'm still have trouble with this. So substituting 3 in for t, and you have 0 on the numerator, and -3 on the denominator, which suggests it'll tend to 0, as t approaches 3?
But when t=3 as well. So then you'd have 0/0 which is undefined?
Excellent. Thanks a lot. It tends to 1/2.Multiply and divide by its conjugate, that is