Results 1 to 2 of 2

Math Help - Calculus Derivative HELP! Please

  1. #1
    Junior Member
    Joined
    Jul 2008
    Posts
    46

    Calculus Derivative HELP! Please

    Can some one help explain this to me i think i am suppose to the quotient rule to solve this.
    Consider the function h(x), for which h(4)=4 and h(prime)(4)=(-4) or the derivative of h^1(4)=(-4)
    Find F^1(4) for the function f(x)=(h(x))/(x)
    Hopefully i explained that right
    Thanks to anyone who can help
    AC
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member

    Joined
    May 2006
    From
    Lexington, MA (USA)
    Posts
    11,683
    Thanks
    615
    Hello, Casas4!

    By the way, the derivative is written: f'(x) ... " f prime" ... not f^1


    Consider the function h(x), for which h(4)=4 and h'(4)= \text{-}4

    Find f'(4) where: f(x)\:=\:\frac{h(x)}{x}

    We are given: . f(x) \:=\:\frac{h(x)}{x}

    Quotient Rule: . f'(x) \;=\;\frac{x\!\cdot\!h'(x) - h(x)}{x^2}


    Therefore: . f'(4) \;=\;\frac{4\!\cdot\!h'(4) - h(4)}{4^2} \;=\;\frac{4(\text{-}4) - 4}{16} \;=\;\frac{\text{-}20}{16} \;=\;\boxed{-\frac{5}{4}}

    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Calculus Derivative Help
    Posted in the Calculus Forum
    Replies: 1
    Last Post: September 16th 2009, 01:57 PM
  2. Calculus Derivative
    Posted in the Calculus Forum
    Replies: 3
    Last Post: January 30th 2009, 12:25 PM
  3. Calculus Derivative.
    Posted in the Calculus Forum
    Replies: 1
    Last Post: January 29th 2009, 12:55 AM
  4. Calculus Derivative
    Posted in the Calculus Forum
    Replies: 2
    Last Post: January 28th 2009, 06:21 PM
  5. calculus derivative help
    Posted in the Calculus Forum
    Replies: 1
    Last Post: January 19th 2009, 03:53 PM

Search Tags


/mathhelpforum @mathhelpforum