300N is on the x-axis (-300,0)
and 200N (100,173) is in a 60 degree angle from the x-axis
How do I find the magnitude of the resultant force and the angle it makes w/ the positive x-axis?
Thanks in advanced.
Let $\displaystyle \bold F_1=\left<-300,~0\right>~N$ and $\displaystyle \bold F_2=\left<100,~173\right>~N$
The resultant force vector $\displaystyle \bold R=\bold F_1+\bold F_2\implies \bold R=\left<-300+100,~0+173\right>~N\implies \color{red}\boxed{\bold R=\left<-200,~173\right>~N}$
The magnitude of the resultant force would be $\displaystyle ||\bold R||=\sqrt{(-200)^2+(173)^2}\implies \color{red}\boxed{||\bold R||\approx 264.44~N}$
I leave it for you to find the angle, given that $\displaystyle \vartheta=\tan^{-1}\left(\frac{R_y}{R_x}\right)$
Does this make sense?
--Chris