How do i start this problem ∫ 8 csc(8x-9)dx
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$\displaystyle \int \csc{u} \, du = -\ln|\csc{u} + \cot{u}| + C$
i don't understand?
you don't know the antiderivative for the cosecant function?
no im sorry i sooooo lost. Can u show me step by step the test is 2morrow
skeeter continue plz this is helping me out as well
this one to
hey bigton we are in the same boat
this is an indfintie and definite integral evaluation problem
Originally Posted by theflyingcow How do i start this problem ∫ 8 csc(8x-9)dx the straight forward way to do this is by substitution. let $\displaystyle u = 8x - 9$ $\displaystyle \Rightarrow du = 8~dx$ and low and behold, we have $\displaystyle 8~dx$ in our integrand thus, our integral becomes $\displaystyle \int \csc u~du$
so how do u continue it because i thought the 8 would be in front of the integral
Originally Posted by theflyingcow so how do u continue it because i thought the 8 would be in front of the integral $\displaystyle \int\csc(ax+b)dx\overbrace{\mapsto}^{u=ax+b}\frac{ 1}{a}\int\csc(u)du$ Let $\displaystyle v=2\arctan(v)$ to find the second integral
wow i never heard of arc
Originally Posted by theflyingcow wow i never heard of arc $\displaystyle \arctan(x)=\tan^{-1}(x)$
but my teacher never used inverse tan
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