We define a sequence recursively in the following way:
s1=2 and sn=3+2sn−1 for n1
- Show that sn is an increasing sequence,
- Show that sn is bounded from above,
- Compute limnsn
1.3+(2sn)−1 < 3+2(sn+1)−1
3+2sn-1 < 3+2sn+1
increasing for all values n
2... i don't believe it is bounded from above,
A squence (Sn) is bounded above if there is a number M such that
Sn<= M for all n>=1 as this is continues to increase there's no M.
A squence (Sn) is bounded below if there is a number M such that
M<= Sn for all n>=1 this however is true. it is bounded below. M<2
3. limnsn of 3+2sn-1
The intended recurrence is that given in MrF's post.
(If you continue responding inappropriatly to posts that you obviously have limmited understanding of I will start issuing infractions, and if I get fed up with that I will just ban you to save tha agravation)