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Math Help - HELP!!! derivative!

  1. #1
    Newbie
    Joined
    Oct 2008
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    1

    HELP!!! derivative!

    How do I find the derivative of
    y = ln(x) - 1
    ln^2(x)

    ?? i tried so many ways... it never turns out right. according to the calculator anyway.

    thanks in advance!
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  2. #2
    Junior Member
    Joined
    Aug 2008
    Posts
    53
    whats the ln^2 (x)

    is it
    ln(x^2)
    or
    (ln(x))^2

    review ur log properties this ones pretty easy
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  3. #3
    Member Jason Bourne's Avatar
    Joined
    Nov 2007
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    Quote Originally Posted by canonind View Post
    How do I find the derivative of
    y = ln(x) - 1
    ln^2(x)

    ?? i tried so many ways... it never turns out right. according to the calculator anyway.

    thanks in advance!
    y = (\ln(x) - 1) \cdot \frac{1}{(\ln(x))^2}

    \frac{dy}{dx} = \frac{1}{x} \cdot (ln(x))^{-2} + \frac{-2(ln(x))^{-3}}{x} \cdot (ln(x)-1)

    Using the product rule.
    Then Simplify to:

    \frac{dy}{dx} = \frac{1}{x(ln(x))^2}\{\frac{2}{ln(x)} - 1 \}

    Understand?
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