y=2^3x^2
i dont know how to do this question at all, any help would be greatly appreciated.
And what is the question?
Would it be: Find the dy/dx?
y = 2^(3x^2)
d/dx a^u = ln(a)*a^u *du/dx
So,
dy/dx = ln(2)*[2^(3x^2)]*6x
dy/dx = 6ln(2)*x*2^(3x^2) ---------answer
dy/dx = 6ln(2) *x *8^(x^2)
dy/dx = ln(2^6) *x *8^(x^2)
dy/dx = ln(64) *x *8^(x^2)
------------------
Or,
y = 2^(3x^2)
y = (2^3)^(x^2)
y = 8^(x^2)
dy/dx = ln(8) *8^(x^2) *2x
dy/dx = 2ln(8) *x *8^(x^2)
dy/dx = ln(8^2) *x *8^(x^2)
dy/dx = ln(64) *x *8^(x^2)