Thread: Limit and Chain Rule Questions

Hi, can someone help me with this?

lim x->0

I tried multiplying by the conjugate then using the trig identity for tan, but I got a bunch of mess I don't know what to do with.

Also, for

lim x->0

is the limit -8? just want to make sure that's right.

and how do I solve this:

let F(x) = h(g(f(x))), where f(4) = 7, g(7) = 8, f '(4) = 3, g '(7) = 8, and h '(8) = 2

then find F'(4)

confused as how to do this

thanks!

now take the limit as x approaches 0.


for the 2nd limit ... if x is approaching 0, then limit is


last one, use the chain rule ...



now sub in x = 4 and evaluate.

thanks, still confused about the last one though

can anyone help me find F'(4) if
F(x) = h(g(f(x))), where f(4) = 7, g(7) = 8, f '(4) = 3, g '(7) = 8, and h '(8) = 2

not sure where to sub in 4 or whatever.

ahh of course, how did I not see that??

thanks!