now take the limit as x approaches 0.
for the 2nd limit ... if x is approaching 0, then limit is
last one, use the chain rule ...
now sub in x = 4 and evaluate.
Hi, can someone help me with this?
lim x->0
I tried multiplying by the conjugate then using the trig identity for tan, but I got a bunch of mess I don't know what to do with.
Also, for
lim x->0
is the limit -8? just want to make sure that's right.
and how do I solve this:
let F(x) = h(g(f(x))), where f(4) = 7, g(7) = 8, f '(4) = 3, g '(7) = 8, and h '(8) = 2
then find F'(4)
confused as how to do this
thanks!