Prove that if u is parallel to v then |u · v| = |u||v|.

Prove that if u is not parallel to v then |u · v| < |u||v|.

Can anyone help me prove this please

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- October 13th 2008, 12:27 PMthe1u2001[SOLVED] Vector ProofProve that if u is parallel to v then |u · v| = |u||v|.

Prove that if u is not parallel to v then |u · v| < |u||v|.

Can anyone help me prove this please

- October 13th 2008, 12:31 PMJhevon
- October 13th 2008, 12:33 PMthe1u2001
- October 13th 2008, 12:35 PMJhevon
- October 13th 2008, 12:46 PMthe1u2001
- October 13th 2008, 12:49 PMJhevon
start with the formula i gave you. say what theta has to be if the vectors are parallel and plug the values in and show what happens.

then say what theta has to be for the vectors not to be parallel and show what happens.

pretty straight forward stuff. don't fall into the trap of making this more complicated than it already is just because the word "prove" is there.

you may also want to say, - October 13th 2008, 01:29 PMthe1u2001
K thank for the help and i have proved that if u is parallel that theta=0

but i am find it difficlut for if U is not parallel. is

theta http://www.mathhelpforum.com/math-he...b7f5ef8f-1.gif - October 13th 2008, 01:34 PMo_O
Since the two vectors are not parallel, i.e. , then that must mean . Can you see how to get inequality from now?

- October 13th 2008, 01:38 PMthe1u2001