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Math Help - equation of tangent line

  1. #1
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    Exclamation equation of tangent line

    find the equation of the tangent line to the curve at the given point.

    y=(1+2x)^10 (0,1)
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  2. #2
    Member maybeline9216's Avatar
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    "y=(1+2x)^10" Is this the equation of the curve??
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  3. #3
    Member maybeline9216's Avatar
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    First find what is dy/dx.

    Note that the gradient of the tangent to the curve at x=0 is equal to the gradient of the curve at the pt. x=0

    To find dy/dx, use chain rule.
    dy/dx=10{(1+2x)^9} x 2
    =20{(1+2x)^9}

    Then sub x=0 into dy/dx.
    U will get dy/dx=20

    Eqn.of tangent to the curve at x=0
    => [(y-1)/x] = 20
    Complete the rest on your own...
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