How would i differentiate this
$\displaystyle
ln(lnx^2)
$
im trying to do it right now but im getting alot
of fractions
i think i got it does it look something like this
(1/lnx^2) (2/x)
How would i differentiate this
$\displaystyle
ln(lnx^2)
$
im trying to do it right now but im getting alot
of fractions
i think i got it does it look something like this
(1/lnx^2) (2/x)
Your answer is correct.
You could have made life a bit easier for yourself by using properties of logarithms. In fact, $\displaystyle \ln(x^2)=2\ln x$, so $\displaystyle \ln(\ln(x^2)) = \ln(2\ln x) = \ln2 + \ln(\ln x)$. Then when you differentiate, the first term is constant, so it disappears and you only have to deal with the second term.