How would i differentiate this

$\displaystyle

ln(lnx^2)

$

im trying to do it right now but im getting alot

of fractions

i think i got it does it look something like this

(1/lnx^2) (2/x)

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- Oct 13th 2008, 12:27 AMjohn doeLogarithmic Differentiation
How would i differentiate this

$\displaystyle

ln(lnx^2)

$

im trying to do it right now but im getting alot

of fractions

i think i got it does it look something like this

(1/lnx^2) (2/x) - Oct 13th 2008, 12:54 AMOpalg
Your answer is correct.

You could have made life a bit easier for yourself by using properties of logarithms. In fact, $\displaystyle \ln(x^2)=2\ln x$, so $\displaystyle \ln(\ln(x^2)) = \ln(2\ln x) = \ln2 + \ln(\ln x)$. Then when you differentiate, the first term is constant, so it disappears and you only have to deal with the second term. - Oct 13th 2008, 02:18 AMJasoniumanswer
Isn't it 1/(xlnx) ?

- Oct 13th 2008, 02:53 AMmr fantastic
- Oct 13th 2008, 02:56 AMmr fantastic