$\displaystyle f(0)=f(2)=0 $ $\displaystyle f'(x)>0,f''(x)>0 $ (if x<1) $\displaystyle f'(1)=0 $ $\displaystyle f'(x)<0,f''(x)<0 $ (if x>1) Anyone know how to graph this
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hm.. I don't know. Won't the sudden shift in concavity and slope make the f'(1) undefined? does anyone else see how that can be 0?
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