y = [x + (x + sin²x)³]^4
I ended up getting
4[x + x(x+sin²x)³]³ * 3x(sin²x)² * 2cosx
Am I right???! If not, can someone seriously walk me through this? This was a really messy problem for me.
y = [x + (x + sin²x)³]^4
I ended up getting
4[x + x(x+sin²x)³]³ * 3x(sin²x)² * 2cosx
Am I right???! If not, can someone seriously walk me through this? This was a really messy problem for me.
nope, not right.
how about i give you a few hints and you try again and see where we get
to find the derivative of $\displaystyle x(\sin^2 x)^3$ you need to use the product rule
when you are differentiating the $\displaystyle (\sin^2 x)^3$ part, you need to use the chain rule. it would be easier to write $\displaystyle (\sin^2 x)^3$ as $\displaystyle \sin^6 x$ by the way