Find the equation of the tangent line to the graph C at the point (-3,8) for the parametric equations: and
For this, The derivative is a vertical line, where x=-3. Can you have a vertical derivative? Is the answer no solution or x=-3?
Thank You.
Find the equation of the tangent line to the graph C at the point (-3,8) for the parametric equations: and
For this, The derivative is a vertical line, where x=-3. Can you have a vertical derivative? Is the answer no solution or x=-3?
Thank You.
ok, if x = -3, then what is t? you will need this value to find the derivative
now,
and you plug in the value of t to find your slope.
then all you have to do is find the equation of the line with the above slope passing through (-3, 8), which i suppose you know how to do
I plugged in the point (-3,8) into the x(t) and y(t) equations, and I got:
for I got and if you plug in 2, you get 12/0, which is undef.
Did I do it correctly?
Can the derivative be a vertical line?
Since the derivative is a vertical line, and it goes through the point (-3,8), Is the equation for the derivative x=-3?
no, i told you to solve for t, how is it that you can assume you already have it? and how is it you have two different t values for the same point (you assumed t = 3 for x and t = 8 for y)?
we have and
that means and
solve for that satisfies both equations.
then continue to do the problem.