Find the derivative of f(x)=e^4x(x^2+3x)
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$\displaystyle f(x) = e^{4x}(x^2 + 3x)$ $\displaystyle f'(x) = e^{4x}(2x + 3) + 4e^{4x}(x^2 + 3x)$ $\displaystyle f'(x) = e^{4x}[(2x+3) + 4(x^2 + 3x)]$ I'll leave you to clean up the algebra from here.
whoa. how did you do that?
product rule + chain rule with the exponential function
oh ok. thanks!
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