a particle moves along the x-axis in such a way that at time t>0 its position is x=sin(e^t)
at what time does the particle have a velocity of zero?
I take the derivative and get (e^t)*cos(e^t)
so when does that equal zero?
e^t is never zero, right?
so when does cos(e^t) equal zero?
I'm not sure how to solve a trig function with a variable argument.
but some tips. put a \ before the log so it looks nicer. that is, type \log_e ...
also, for the record, we do not write , instead, we write . that is, the natural log is the logarithm to the base
you mean t = 1.then find the earliest instance ie when
yes, but again, use "ln" instead
by the way, the problem never asked for the earliest time. so just state the full answer.