Hi,

how do you go about integrating this:

sin(t)*cos(n*t) with respect to t?

Thanks

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- Oct 11th 2008, 04:11 PMhashiintegrating..
Hi,

how do you go about integrating this:

sin(t)*cos(n*t) with respect to t?

Thanks - Oct 11th 2008, 04:58 PMNacho
$\displaystyle

\sin (x)\cos (y) = \frac{{\sin \left( {x - y} \right) + \sin \left( {x + y} \right)}}

{2}

$

can you continue? - Oct 11th 2008, 04:59 PMRedBarchetta
Well, assuming n is a constant, then use this rule to split the integral up into something more manageable.

$\displaystyle

\sin (mx)\cos (nx) = \frac{1}

{2}\left[ {\sin (m - n)x + \sin (m + n)x} \right]

$

Let m=1 and n=n. (Cool) - Oct 11th 2008, 05:19 PMhashi
thank you guys.. i can do it now!

:D