x^2y" - 2xy' + 2y = 1/x^2 I think you do this by variation of parameters but i'm getting stuck on finding the solution
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Originally Posted by action259 x^2y" - 2xy' + 2y = 1/x^2 I think you do this by variation of parameters but i'm getting stuck on finding the solution Actually this is a Cauchy-Linear Equation. Use the subsitution, $\displaystyle x=e^z$.
i used the Cauchy-Linear method to find the homgeneous solution but don't you still need to use variation of parameters to find the particular solution? this is where i seem to be getting stuck
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